⚡ TL;DR
Print the cross/plus sign star pattern in Python. Complete working code, expected output, algorithm explanation, and practice variations for beginners learning loops.
The Cross/Plus Sign Star pattern is a classic loop exercise. Here’s the complete implementation in Python with working code and output.
Pattern to Print
*
*
*****
*
*Implementation
def cross(n):
mid = n // 2
for i in range(n):
for j in range(n):
print('*' if i == mid or j == mid else ' ', end='')
print()
cross(5)Output
*
*
*****
*
*How It Works
Print a star wherever the row equals the middle index OR the column equals the middle index.
Practice Variations
- Try printing the pattern with a different character (e.g.,
#or+) - Modify the code to accept the pattern size as user input
- Combine this pattern with its inverse to create a more complex shape
Complexity
- Time: O(n²) — the grid or line count grows quadratically
- Space: O(1) — only loop counters are needed
Related Patterns
- Cross/Plus Sign Star in Dart
- Cross/Plus Sign Star in Go
- Cross/Plus Sign Star in Swift
- Christmas Tree Star in Python
- Up Arrow Star in Python
- K Shape Star in Python
FAQ
How do you print the Cross/Plus Sign Star pattern in Python?
Use nested loops: the outer loop walks through the rows while the inner loop prints the characters or values for each row. The complete Python implementation with expected output is shown in the sections above.
What is the time complexity of the Cross/Plus Sign Star pattern in Python?
The time complexity is O(n²) and the space complexity is O(1), since the pattern is built with a fixed number of loop counters and printed row by row.
Happy coding!
